Math thing, lol

....
No.
Maybe I'm being too simplistic about this, but I'm getting 11. I guess sooner or later we'll all share our reasonings on this.
5. They simply took their share and went back to sleep. The next day, they ate them, and since there were none left over, they did not give any to poor monkeydude. Prolly 'cuz he was from SPACE.
>_>


Let me simplify this: They are stupid, so they divide whats there. No one can tell why the pile seems so small then ext morning.
Maybe they thought they ate too much?

Wait, maths?

Gkk!
How about 0? Maybe the coconuts were a mirage. They each took 0, and gave the monkey the remainder - 0. Man, those guys are insane.

But I'm not.

...what?

...I'M NOT INSANE! STOP STARING AT ME!

Wait, how about... 5 is the lowest I can figure out, unless they split coconuts.
Its a REMAINDER. If it was 5 the second/third/fourth/fifth guy would not get a cocnut, and the monkey would get 4.
The way I reached 11 was that, reasonably, they're not going to split up a whole coconut into parts, so they must have at least six in the beginning to each have one and be able to consider that there'd be a "remainder" left for the monkey. Then add five more, as if there'd been any less they wouldn't have been able to ignore the splitting problem the next day, yet there need not be more because giving the monkey a remainder wasn't necessary but was merely an initial consideration.
Whoever answered -4 was a complete idiot. I mean it. I hate his guts.
That was me.
X. There are X coconuts.

Quote (Sharmandra)

That was me.

There you go. >>

Explain to me, how exactly can you have a negative amounts of coconuts?
IT was some really smart math dude >_>

who said that each guy got -4 coconuts >_>
You cannot have an negative amounts of coconuts. >>

Come on, think about it. This math problem is a image of a real life situation, not an complex math equation like X^Y2 * 45Z*X. It's people on an island with some coconuts.

The amount of coconuts cannot be negative because that crashes with reality. It would have been possible if this was pure math, because while the amounts of coconuts can never be below zero, X, in math terms, can be anything.
The answer is that there is not enough information given to actually answer the problem...Especially since you say there has to be a remainder, which means it can really be any number as long as five goes into it at least twice. If you are just looking for the lowest possible number...Then 11 or 12 depending on how many times the monkey takes coconuts.
Kind of like in our math class:

When we are finding the domain for stuff, sometimes you have to use logic; you are not going to have a negative number of concert tickets, or half marble in a bag.
...
Can you repeat the question?
It's obvious that there were 10 coco nuts That way they each got one and the monkey got five, and the next day they divided them up again, and themonkey got the remainder of 0.
If the number of coconuts was divisible evenly by 5, they would have simply split them all among themselves, leaving no consideration of the necessary remainder for the monkey in the first place.

Quote (Heat Sonata)

If the number of coconuts was divisible evenly by 5, they would have simply split them all among themselves, leaving no consideration of the necessary remainder for the monkey in the first place.

Not neceseraly, as they are moronic enough to share with a monkey in the first place.